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zhpipo16

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  1. hello again in the first message on this topic there are a atached file where i send the VI whith a pecture of what i wnat and what i get. please lokk at the first message and you will be understand. of any other question im here.but quiqly the work sould be finishedtomorow please. thank you.
  2. QUOTE (Kevin Payne @ Jun 12 2008, 10:11 AM) yes kivin if you want wich commandes i sent? i send the SCPI commandes and all commandes work, but the last commandes is (TRAC:READ?) for reading the values and i had a signal but it is not correct do understand me? else i don't now what you want exactely for explining?
  3. but i said e(t)=5sin(100t); so Amplitide=5v frequency wt=100 and f=2*3.14*w but my programme will acquit from any e(t); and it's good (look my attached file in th firste msg) but my probleme is with the buffer when i apply "read" and my friends this work should be finished this friday, so help me please
  4. QUOTE (Kevin Payne @ Jun 9 2008, 08:44 AM) hello; yes Kevin i want to visualise a current. 1* i will apply e(t)=5sin(100t) 2* the voltage wille be sin v(t)=x*e(t) 3*the current i(t)=v(t)/R so the currant have a same form of voltage ok? and i conect a Keithley 6487 with a circuit serialy not parallèle, so i can make this? and thank you
  5. i am waiting a help please members he doesn't undertand Clio please if you don't now what is mean a driver of instrument please download any driver from for example www.keithley.com and look his VIs, you will be find the write and the read. but my problem is not on the writ and the read i now this functions; my problem is with a buffer ok? :headbang:
  6. so, i wait a long time for a technical answer, and finaly i get this message? dear clio75 do you see a the attached file? and are you understand my first message(explaining for my program)? this is my project for my end of study and this problem is a 10% from my total work, it's the only problem in this work. And for your question i say: yes, the driver of the keithley6487 has a VI (read) and vi (writ) just like visa read visa write and i take this VIs of driver. So if you have a help , help me else i have not a time please ...
  7. but why i have not one answer her please help me
  8. any answer friends help me please :headbang: .
  9. QUOTE (JasonXCX @ May 31 2008, 09:15 AM) hello i speak french very well and that mean( chose sine or squar signale with this key (true/false) it is for generating a sine or square signal)
  10. hello; i get a problème again . well, this is my work (with keithley6487) 1*i have a circuit with a resistance and a diode 2*inject a tension sin with GBF on input(diode) (1) 3*receive a signal from the output (2) 4*but my program show me in the graphe this (3) 5* i receive a signal with the buffer read command (TRAC:DATA?) 6* i make a 200 reading and size of buffer 200 i want to now where is the problem why i had not like signal (2)? help me please (1), (2) and (3) are in the picture
  11. QUOTE (normandinf @ Jun 3 2008, 09:24 PM) thank you friend normandif i will do this and i will tel you ok?
  12. this is my VI , but i don't now how i can make a graph after this commande please help me. this is my VI , but i don't now how i can make a graph after this commande please help me. i use the VIs of driver of keithley 6487.
  13. ok friend and thank you; so after this commands i take a READ or READ DATA VI or make a connection with graph or........ and really thank you very match :thumbup:
  14. thank you for your interesting yes i have a driver but the sous VI READ for example or READ DATA cans read one value or currant but i want to read a complete signal do you understand me friend ? any help....... thank you again.
  15. hello every body i am new in this forum and i want a help please i want to automate a Keithley 6487 instrument with labVIEW and RS232 and my desire function is to acquit a signal from this instrument and trace him in the graph; so please help me NB: the Kethley 6487 is an instrument for measurement (low currant and hay resistance) and mu work is to inject a signal sin of tension on the base of a transistor and acquit a signal from the output (collector) ; it is a sin signal so how i can do that please . thank you
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