Mark Smith Posted November 4, 2009 Report Share Posted November 4, 2009 I need to get the access scope of a VI programmatically - I'm creating a tool to produce documentation for my classes and I want to know whether or not a VI is public or private. If it's private, then I don't need to add it to the documentation since the developer will never use it directly (If someone already has a tool to do this sort of thing, I'd love to see it!) I searched the forum and found this thread http://lavag.org/top...__fromsearch__1 where AQ says "Asking a VI "are you a private VI" is easy enough -- use the VI ref to get the lib item ref and then ask for scope, which will take care of checking virtual folder settings. " Except that the Get Source Scope method also wants a source ref (type is ProjectItem). How do I get this ref? Do I need to open a project and find this particular item? Or is it exposed somewhere else? Thanks, Mark I'm using LV 8.6.1 Quote Link to comment
Francois Normandin Posted November 4, 2009 Report Share Posted November 4, 2009 The children of a LVClass library are Project Items. Sorry I don't have 8.6 available at the moment. Here's a screenshot (LV2009 snippet). I was being lousy... there's another computer right next to me with LV 8.6... AccessScope_LV86.vi 2 Quote Link to comment
Mark Smith Posted November 4, 2009 Author Report Share Posted November 4, 2009 The children of a LVClass library are Project Items. Sorry I don't have 8.6 available at the moment. Here's a screenshot (LV2009 snippet). I was being lousy... there's another computer right next to me with LV 8.6... AccessScope_LV86.vi Thank you ... LAVA to the rescue! This will let me do what I need. I'm still interested to know if could get the access scope directly from a VI ref to a class member. Mark Quote Link to comment
Francois Normandin Posted November 5, 2009 Report Share Posted November 5, 2009 Hi Mark, You can do it even if the class is not loaded. If your VI is not part of a library (lvclass, lvlib, xcontrol, ...) then it's scope will be "invalid". Otherwise, it's about the same thing except you start from the VI reference and check it's owning library reference. If it exists, then it's part of a library for which you can find a match by using the ProjectItem's VI reference. The VI reference is not always valid (because all library members are not automatically VIs) but if you can sort out the errors and invalid references, then you can match the correct ProjectItem with it's associated VI reference. Note that this works for any libraries, not just lvclasses. If your VI is a private member of a lvlib, then it's gonna return the correct access scope too. AccessScopeFromVI.vi 1 Quote Link to comment
Mark Smith Posted November 5, 2009 Author Report Share Posted November 5, 2009 Hi Mark, You can do it even if the class is not loaded. If your VI is not part of a library (lvclass, lvlib, xcontrol, ...) then it's scope will be "invalid". Otherwise, it's about the same thing except you start from the VI reference and check it's owning library reference. If it exists, then it's part of a library for which you can find a match by using the ProjectItem's VI reference. The VI reference is not always valid (because all library members are not automatically VIs) but if you can sort out the errors and invalid references, then you can match the correct ProjectItem with it's associated VI reference. Note that this works for any libraries, not just lvclasses. If your VI is a private member of a lvlib, then it's gonna return the correct access scope too. AccessScopeFromVI.vi Thanks once again. This does explain what is actually happening. The VI knows it's part of a library but it appears that only the library knows the VI's scope. I thought from that original snippet from AQ (from the linked thread) that the VI also would know and might be able to report its scope, but apparently my interpretation was incorrect. Mark Quote Link to comment
Francois Normandin Posted November 5, 2009 Report Share Posted November 5, 2009 Thanks once again. This does explain what is actually happening. The VI knows it's part of a library but it appears that only the library knows the VI's scope. I thought from that original snippet from AQ (from the linked thread) that the VI also would know and might be able to report its scope, but apparently my interpretation was incorrect. Mark Indeed. A VI by itself doesn't have a scope. You can disconnect a VI from its library and it's gonna be a plain ol' VI. This can be useful to remember if you've got a corrupted library. It never happened to me in a lvclass, but it did (in 8.2 if I'm not mistaken) for lvlibs. I had to disconnect the VIs from their corrupted library, otherwise I couldn't access it. Deleting the library file is not enough because the VI knows it is linked to it. Quote Link to comment
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.