Jyothis Posted June 7 Report Share Posted June 7 What is this function and why is this error popping up ?? Quote Link to comment
LogMAN Posted June 7 Report Share Posted June 7 Welcome to LavaG. This is a queue: What Is a Queue in LabVIEW? - NI You probably tried to delete the control inside the queue indicator. This does not work because a queue must always have a subtype. As the error message suggests, simply drag a new type on the queue indicator and it will replace the existing one. Alternatively, use the 'Obtain Queue' function on your block diagram to create a new indicator based on the configured input type. 1 Quote Link to comment
crelf Posted June 7 Report Share Posted June 7 Also, please post the VI - the issue might be in the code, not the front panel. Quote Link to comment
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