Jyothis Posted June 7, 2024 Report Posted June 7, 2024 What is this function and why is this error popping up ?? Quote
LogMAN Posted June 7, 2024 Report Posted June 7, 2024 Welcome to LavaG. This is a queue: What Is a Queue in LabVIEW? - NI You probably tried to delete the control inside the queue indicator. This does not work because a queue must always have a subtype. As the error message suggests, simply drag a new type on the queue indicator and it will replace the existing one. Alternatively, use the 'Obtain Queue' function on your block diagram to create a new indicator based on the configured input type. 1 Quote
crelf Posted June 7, 2024 Report Posted June 7, 2024 Also, please post the VI - the issue might be in the code, not the front panel. Quote
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