GSR Posted March 5, 2010 Report Share Posted March 5, 2010 I learned this topic years ago, and I want someone to confirm my understanding Assume I have 2 diodes. The reverse breakdown (BD) voltages are 10V and 6V respectively. They are connected in series. -----|>|----------|>|------- | ..............................| | ..............................| | ..............................| ----------- (-8V+)--------- I think if the 10V BD-diode is on the right and the 6V BD-diode is on the left, both of them will still be OK If they switch the position, the 6V BD-diode will breakdown Am I right???? Quote Link to comment
jyang72211 Posted March 6, 2010 Report Share Posted March 6, 2010 I learned this topic years ago, and I want someone to confirm my understanding Assume I have 2 diodes. The reverse breakdown (BD) voltages are 10V and 6V respectively. They are connected in series. -----|>|----------|>|------- | ..............................| | ..............................| | ..............................| ----------- (-8V+)--------- I think if the 10V BD-diode is on the right and the 6V BD-diode is on the left, both of them will still be OK If they switch the position, the 6V BD-diode will breakdown Am I right???? NO, the circuit will not breakdown under 16V regardless. Since the diodes are in series, if a breakdown were to occur, both diode must break down. Think about this way, when Diode A breakdown, that means a high current would pass through Diode A. If Diode B is connected in series with Diode A and a high current is going through on Diode A, the same current must go through for Diode B as well. If high current has to go through Diode B, that means Diode B must breakdown as well. Yik Quote Link to comment
JohnRH Posted March 6, 2010 Report Share Posted March 6, 2010 The circuit you are describing would look like this ... ------------|>|------------- | . . . . . . . . . . . . . | | . . . . . . . . . . . . . | ------------|>|------------ | . . . . . . . . . . . . . | | . . . . . . . . . . . . . | ----------- (-8V+)-------- Then, one diode may break down before the other. Quote Link to comment
Rolf Kalbermatter Posted March 11, 2010 Report Share Posted March 11, 2010 I learned this topic years ago, and I want someone to confirm my understanding Assume I have 2 diodes. The reverse breakdown (BD) voltages are 10V and 6V respectively. They are connected in series. -----|>|----------|>|------- | ..............................| | ..............................| | ..............................| ----------- (-8V+)--------- I think if the 10V BD-diode is on the right and the 6V BD-diode is on the left, both of them will still be OK If they switch the position, the 6V BD-diode will breakdown Am I right???? The order of the diodes should have no influence whatsover, assuming no other environmental influences (PCB leakage currents, dirt, etc) would influence them in one way or the other. Quote Link to comment
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