Eugen Graf

QUOTE(Tomi Maila @ Apr 17 2007, 05:51 PM)

I don't quite understand what is the problem.

Thanks, for answer.

The snippet shows my "send commands to VISA" task. The user can change settings in main task and all other tasks will be updated with new settings (Set Value Property). But VISA Write on attached picture have older settings if a new message comes and sends only by second message to the right interface. Its the dataflow principle of LV.

Eugen

P.S. see here http://forums.lavag.org/index.php?s=&showtopic=2710&view=findpost&p=25858' target="_blank">http://forums.lavag.org/index.php?s=&s...ost&p=25858

P.S. firstly I wanted to replace Queues in tasks with User Events, because I have this problem:

http://forums.lavag.org/index.php?act=attach&type=post&id=5537

How do you think, what is better to use Queues or User Events? What is faster and eats less memory?

QUOTE(Tomi Maila @ Apr 17 2007, 04:58 PM)

Because you should register the event for both event handlers independently...

EDIT: Event registrations are like mail boxes. In your loop you put two loops checking the same mailbox. I guess the timeout occurs because of race condition. Event handler starts to handle event but notices that it's already handled. If you register the event for both loops the timeout doesn't occur. Your upper loop is generating user events for itself in reponse to the same user events. This will not be very wise

Tomi

Thanks, I know its not right to generate event if the same occures, so I will get neverending story in my programm. I want only to understand how user events work.

And I know too, that two event structures in one VI have to be avoided. But my second loop simulates only an another task (other VI, which will be started dynamically).

The aim was to register all events in the main task and handle them in other tasks, I want to commit only the registration refnum to other tasks, but you say its not possible, I have to register events in each task.

Eugen

Who can say why I get the timeout event in the first loop, after clicking on "Generate" button?

Eugen

Why not? It's easy, that are ASCII messages, so you can see all what you send or receive.

Eugen

I found out now, that the error appears if I loaded the VI and want then build an application. The app builder loads the VI into memory too, than I have the DLL twice and get the error.

I post the error message at tuesday, than you can sse what I think.

Eugen

What is with "In Range and Coerce" from the Comparison Palette ?

Eugen

QUOTE(Tomi Maila @ Apr 4 2007, 04:01 PM)

I don't know if you could use the trick where you use static reference to get VI name and then open a reference dynamically with this name. See image in the middle at http://thinkinging.com/2007/03/29/reentrant-vi-clone-name/' target="_blank">Jim Krings blog.

Tomi

I think it can't help, because even using of statical VI reference causes the problem.

Eugen

I think, I change the statical call to dynamical, than I have no problems with (excluding one disadvantage - the name of called VI must stay constant).

Eugen

VI, which calls DLL is not reentrant.

Both VIs are in the same application.

Eugen

Here a interesting statistic about programming languages:

http://www.tiobe.com/index.htm?tiobe_index

Eugen

Can be, that, if I loaded a VI, which calls a DLL, into memory(by opening e.g. from project explorer) and then load a VI, which calls this VI by static reference, then LV tryes to load the DLL twice?

I get errors from DLL if I do that and LV closes immideatly.

Eugen

screenshots

QUOTE(JFM @ Apr 2 2007, 12:16 PM)

Use the break point tool from the Tools-Palette.

When the break point tool is black, it will add a breakpoint, when it is white it will remove a previously added breakpoint.

In your case use the tool and click within the loop.

/J

Thanks, I normally don't use breakpoint tool, so I couln't know this. It was really automatically tool selection, as you wrote.

Eugen

Hello LAVAs,

until debugging I unintentionally clicked on while loop and an breakpoint inside the while loop was created. Now I dont know how to remove it. Here my screenshot. No selection for removing by right klicking on the loop appears.

Eugen

Very helpfull, thanks a lot.

Eugen

QUOTE(LV Punk @ Mar 30 2007, 01:50 PM)

As I understand it, queues will dynamically allocate memory, but free memory only when destroyed. The online help states:

Note

max queue size

only limits the number of elements in the queue. It does not preallocate memory. Enqueue the maximum number of elements and flush the queue to preallocate the queue. The queue reserves more memory as its size increases and releases that memory only when you destroy the queue.

Thank you very much for this information.

QUOTE(LV Punk @ Mar 30 2007, 01:50 PM)

Do you do it in a for loop? So in your initialisation step? Can you post an exapmple? Thanks

QUOTE(LV Punk @ Mar 30 2007, 01:50 PM)

Its right.

Eugen

Hello all,

if I see an unlimited queue size, I think LV must realloc the memory every operation with this queue. Now I ask me, its only if the size is unlimited or the memory will be reallocate if the size is definied?

If the memory will be reallocate, its more more slower as the "normally" queue in other programming languages.

Eugen

Also I defined now my Intro VI to top level VI and call Main VI from there. The effect I want to avoid is avay now.

Eugen

It sounds like a tree control. Don't you have a tree control in your LV version?

Eugen

Thanks, but the presentation is in japan and in the thread from NI forum describes my way to make that, but I still know how to implement it with VI server. My problem is only, that the main VI will be shown for 1 ms or fewer, because its the top level VI.

Eugen

Online users list isnt work. If I say show only registered, they show me all users incl. guests.

Eugen

Hello everybody,

I want to implement a intro window in my application. During starting and initialization of my main, a intro (with groving transparency) window should be shown. Also I can't place the intro subVI to my main, because it will be wait until intro is done. Therefore I start my intro by VI server in the first state of my main state machine. You can see both pictures appended.

The problem is if I start my exe, so top level VI is my main. The window of the main will be shown for few microseconds starting exe. I want avoid it, I want nothing will be shown before intro.

Should I make my intro as top level and start my main there or I can set it in VI settings or exe builder or ini-file?

Thanks, Eugen

Here is my intro VI.

Eugen

QUOTE(LV Punk @ Mar 22 2007, 08:05 PM)

It's a link to a BLOG, don't know if you have any filters or restrictions...

Here's an example of what you can do in LV 8.20 with the Background and Splitter/Pane features

http://forums.lavag.org/index.php?act=attach&type=post&id=5261

http://forums.lavag.org/index.php?act=attach&type=post&id=5262

What a shame!

Its for 8.2 only.

Eugen

I never use express VIs, because I don't know whal happens there. I prefer only simple VIs.

Can thisone help you?

Eugen

QUOTE(dwisti @ Mar 26 2007, 09:09 PM)

Does VMWare Server expire? It was free but my licence says no expiration.

http://forums.lavag.org/index.php?act=attach&type=post&id=5302

Really, i installed that from a c't magazine http://www.heise.de/ct/english/ and there stood its a one-year-license. I look tomorrow on my license info.

Eugen