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liakofan

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About liakofan

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    LAVA groupie

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  • Version
    LabVIEW 2009
  • Since
    2009
  1. Maybe someone else has the same or similar issue so i post what seems to be the solution. I changed the address of the shared variable. It had the DNS name of the PXI and i changed it to the IP address. I don't believe it should make a difference but it stopped giving an error.
  2. Hello everyone, Basically i have 2 VIs, one running on a PXI, lets call it PXI.vi and one on the pc, GUI.vi I started testing my application some days ago and after 3 hours of running i got the error in the picture. Error -1073807339 occured at VISA Write in PXI.vi Reason: Timeout expired before operation completed. Then immediately also this error: Unable to locate variable in the shared variable engine. Deployment of the variable may have failed. I restarted the PXI and started the test and it happened again after 2 hours. The third time even sooner. It is always 2 variables that ca
  3. Kello everyone! I have some instruments which i controll over VISA. the software has two parts: one GUI running on a computer and the program running on the PXI to which the instruments are connected. I would like the user to be able to choose the GPIB address of each instrument on the GUI, so i created a cluster of GPIB controls. My problem is that while the same cluster on the software of the PXI gives the posible addresses from the instruments connected to it, on the GUI it does not. One easy solution is the user to write the number of each instrument and manipulate the string but i
  4. Hello Everyone! I have 3 arrays from which i initialize a .CSV file when i run my VI ( as you can see in the example file.)( i use data from other arrays as well but it is not important ) The First array "customer Number" can be from 0 - 15 The second array "Customer Present" is a Boolean. The Third array will contain some fix values like " milk, meat, clothing....." it will have 14 different categories. The Fifth array will contain the quantity of the products from each category from the previous array. My job is to add in my initialized .CSV file the values from the 4th and 5th array
  5. i believe i am in a very good path. The only thing that is missing is scanning the MoreThan10? array for elements being true because they correspond to another array from which i have to generate a file saying that these elements exceeded 10 errors and reached, this value.
  6. Would somebody please tell me why i can't convert crossrulez example so that it can work with a 16x14 array? have you customized the arrays somehow? I can not figure out what is going wrong. array16x14.vi
  7. you've been a great help! I am stuck on this almost 3 days now.... Don't know if I am doing something wrong but i don't get the results for the columns and the rows.... Also the array is going to change every second and it would be preferred no to have to push " update" every second. Should i just remove the event case and introduce a stacked sequence structure?
  8. Thank you all for your help! Got some really interesting ideas! My array will be changing every second and i would like to know which elements are changing more than 10 times. after the program has finished it should generate a report ( .CSV file ) saying that "these elements generated that many errors", or just more than 10 errors, which sounds easier. my program will run for 24 hours and after it should give the results. Probably i will have to sum the differences of my array from each iteration so at the end i will know the total sum of the changes as well. ( 2nd diagram ) I didn't know
  9. Hello Everyone, I have a 16*16 array with some I32 values and i want to know with each iteration if there is a change in any of the elements. If the number of changes are bigger than 10 there should be a msg saying something. So i subtract my array with the previous one, using feedback node and i add the resulting array to itself. I can check if there is a value inside the last array greater than 10 but i can not figure out how to know what column and row the element is. If anyone could help I would appreciate it. I hope i explained the diagram correctly. Kind Regards<br style="">
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