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question about llb and ctrl + shift + Run


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All the VIs in memory, across the board, including the private ones that are part of LV itself. The only exceptions are VIs that are currently reserved for running. If a VI is not in memory, it doesn't get recompiled. LLBs have no meaning after loading, so the fact that one VI from an LLB is in memory doesn't cause the other VIs in the LLB to be recompiled.

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QUOTE(Aristos Queue @ Oct 4 2007, 04:16 PM)

All the VIs in memory, across the board, including the private ones that are part of LV itself.

I thought it was only VIs in the hierarchy (including vi.lib, of course). Is that wrong (can't check now)?

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